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4logx-6log(x+2) turn into single log
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solving part by part \[4\log(x) = \log(x^4)\] and \[6\log(x+2) = \log(x+2)^6\] from the law of log, log(A)-log(B) = log(A/B) So the above equation should be \[\log(x^4/(x+2)^6)\]
how do you solve it?
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