Question

Y''+9y'=t^2 e^(3t) + 6 solved via y(t)=yc+yp?

Answer 1

homogenous: m^2+9m=0
m(m+9)=0
m = 0 and m = -9
Yh(x) = C1 + C2 e^-9x
y1 = e^0 = 1
y2 = e^-9x
wronskian = W[y1,y2] = 1 e^-9x
0 -9 e^-9x
= -9e^-9x - 0 = -9 e^-9x not equal to 0, means linear free
continue......

Answer 2

yes