Question

how would i go about solving 8e^2x=20. btw we are on logs.

Answer 1

e^2x=20/8
lne^2x = ln (20/8)
2x = ln (20/8)
x = [ln(20/80]/2

Answer 2

\[8e^{2x}=20\]
\[e^{2x}=4\]\[2x=ln(4)\]
\[x=\frac{ln(4)}{2}\]

Answer 3

20/8 = 4 :-??

Answer 4

and since
\[ln(4) = ln(2^2)=2ln(2)\]

\[\frac{ln(4)}{2}=ln(2)\]

Answer 5

ho ho ho

Answer 6

time for me to retire

Answer 7

;-)

Answer 8

\[\frac{ln(5)}{2}\]

Answer 9

or whatever \[\frac{20}{8}\] is

Answer 10

they already answer it in the other question box :D

Answer 11

hope they didn't write
\[\frac{ln(4)}{2}\]!

Answer 12

haha