Question

A population of bacteria is growing according to the equation P(t)=1150e^(0.05(t)). Estimate when the population will exceed 1552.

Answer 1

how do we find t?:) thanks

Answer 2

\[1150e^{.05t}=1552\]
\[e^{.05t}=\frac{1552}{1150}\]
\[.05t=ln(\frac{1552}{1150})\]
\[t=\frac{ln(\frac{1552}{1150})}{.05}\]

Answer 3

thank you!:)

Answer 4

welcome.