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use the definition of the derivative f'(x)=lim x->delta x of (f(x+delta x)-f(x))/delta x of f(x)=2/(x-5)
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sorry , why I post that on your question? ?
ignore that! there was a but on this software
but =bug
alright
Then I oblige to answer your question :). For \(f(x)=2/(x-5)\). The expression become \[\frac{1}{\Delta x}(2/(x+\Delta x -5)-2/(x-5))=\frac{-2\Delta x}{\Delta x(x-5)(x+\Delta x-5)}=\frac{-2}{(x-5)(x+\Delta x-5)}\] As \(\Delta x\to 0\) we have \(-2/(x-5)^2\).
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for some reason i cant see past the second equals sign... :/
Try to refresh the browser. Press F5.
nope still the same thing. and i have a mac. so i dont have f5...
See the attachment.
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