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A country's population in 1995 was 228 million. In 2001 it was 230 million. Estimate the population in 2010 using the exponential growth formula. Round your answer to the nearest million
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\[P _{t}=P _{0}e ^{kt}\] Find k \[230 = 228*e ^{6k}\] \[k = \frac{\ln 230/228}{6}\] Substitute this value in to find P15 2010-1995 = 15 \[P _{15}=228*e ^{15*\ln (230/228)/6}\]
can you solve it for me? i'm not sure how to
i did solve it just calculate P15 using a calculator
how do i do that?
ok can you find ln(230/228) ?
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not sure
press the ln button and then "(230/228)" did you understand any of the steps i did?
i got 0.008733 from the In 230/228. then what??????????????????
They Answer to that is 232. Youre welcome
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