Question

Help plz
1) Find the equation of the line in point-slope form containing the point (-4,7) and parallel to the line 3x-5y=9

Answer 1

hey!
its easy!

Answer 2

1) present given equation in form : y=...
5y=3x-9
y=3/5 *x - 9/5
2) you found that the slope of given line is 3/5
your line = parallel to the give line, so - the same slope;
3) equation of the line containing point (-4,7):
y-7=(3/5) *(x- (-4))
y=(3/5)x +(12/5) +7
y=(3/5)x + 47/5

Answer 3

YeaH! Correct.
i was just about to type it. :)

Answer 4

is this all its asking? cuz i got that answer too but i wasnt sure if it was finished

Answer 5

it fine.
If i had to write it thn, i would hav written:

5y=3x +47.

Answer 6

Ok, but what if its a perpendicular line instead of a parallel line?

Answer 7

use the reciprocal correct? which would be instead of 3/5 => -5/3?

Answer 8

thn v'll apply the formuale:
m1 x m2 = -1

Yeah!
crrect,

Answer 9

so answer would be y = (-5/3)x +(1/3)

Answer 10

there should a cordinate through which u may find
wht is the cordinate?

Answer 11

um you mean the points its containing? its "...containing the point (-4,7) and perpendicular to the line 3x-5y=9"

Answer 12

oh!
thn the gradient of this line will b 1/3.

Answer 13

thn u may add the value of y-intercept
which u may find with a cordinate & the gradient 1/3

Answer 14

i dont understand, what do u mean?

Answer 15

till where u understood?

Answer 16

i got the answer of \[y = (-5 \ 3)x + (1 \ 3)\] <

Answer 17

weird... those two are fractions* -5/3 and 1/3

Answer 18

this is the main line on which there is a perpendicular?

Answer 19

i believe so, thats what i solved for using the point slope formula. and i got the slope from the problem i had done above with the parallel line

Answer 20

sorry man!
i gotta go now.

tc. :)