You attach a powerful spring to a high ceiling 10 meters above you. You attach a waterballoon filled with about 10 liters of cold delicious Tiger Beer to the end of the spring. After the balloon is attached the spring hangs down 5 meters. Now you stretch the spring manually to the floor. Write a differential equation describing the motion of the balloon up until it hits the ceiling. You can assume the damping force due to air resistance is minus 2 times the speed of the balloon. Solve your differential equation. Also, why in the world would you do this? I mean the beer shower would be pretty a

Question

anonymous · Answer

Do you want the answer or not?  Or is this just a joke?

anonymous · Answer

the answer

anonymous · Answer

okay:
Friction= -2v
Restoring force = kx
Gravity = -mg
Fnet = ma
ma = kx - mg -2v
m(d^2x/dt^2) = kx - mg - 2 (dx/dt)

anonymous · Answer

$$m(d ^{2}x/dt ^{2}) = kx - mg - 2(dx/dt)$$