Question

hi all

Answer 1

I need some help with some math :/

Answer 2

If sin theta = 8/9, 0<theta<Pi/2, find the exact value of each of the following. sin2theta

Answer 3

sin^2theta+cos^2theta=1

we know tht sin theta = 8/9, therefore sin^2theta = 64/81

by re arrnging we get

cos^2theta = 1 - 64/81
cos^2 theta = 17/81
cos theta = sqrt(17)/9

sin2theta=2sin theta x cos theta

=2sin(8/9)x cos(sqrt(17)/9)

Answer 4

is there a times between x and cos?

Answer 5

yeah it is a times

Answer 6

correct answer was 16sqrt17/81 :(

Answer 7

but i get another shot

Answer 8

If sin(theta)=1/6, 0<(theta)<Pi/2, find the exact value for each of the following. sin(2theta)

Answer 9

yeah thats the answer
sintheta = 8/9
cos theta=sqrt(17)/9

2(8/9) x sqrt(17)/9

=16sqrt17/81