sketch the triangle with vertics A(-5,12), B(4,-2) and C(1,-6)
Find the slope of the side AC.
Find the slope of the altitude form point B to side AC
fIND an equation for the line that includes the altitude from point B to side AC
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OpenStudy (anonymous):
Do you recall the formula for the slope of a line given 2 points on the line?
OpenStudy (toxicsugar22):
yes
OpenStudy (anonymous):
So use it to find the slope of the side AC.
OpenStudy (anonymous):
Once you have that you can find the perpendicular slope by taking the negative reciprocal
OpenStudy (anonymous):
which is the slope of the altitude from B to the side AC. Then with that slope you can write the equation of the line with that slope that intersects B.
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OpenStudy (toxicsugar22):
im guessing -3
OpenStudy (toxicsugar22):
is that right
OpenStudy (anonymous):
-3 is the slope of AC
OpenStudy (toxicsugar22):
ok
OpenStudy (anonymous):
So what is the slope perpendicular to that?
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OpenStudy (toxicsugar22):
so what would be the equatin
OpenStudy (toxicsugar22):
1/-3
OpenStudy (toxicsugar22):
right
OpenStudy (anonymous):
No, negative reciprocal is perpendicular.
OpenStudy (anonymous):
so 1/3
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OpenStudy (anonymous):
So now, you have a point B and the slope. Do you know the formula for the equation of the line given a point and a slope?
OpenStudy (toxicsugar22):
y=1/3x+2
OpenStudy (toxicsugar22):
is that right
OpenStudy (toxicsugar22):
is thais right
OpenStudy (anonymous):
I don't think so. It should be \(y+2 = \frac{1}{3}(x-4)\)
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OpenStudy (toxicsugar22):
i think we put it in slope intecept form
OpenStudy (anonymous):
sure, but I don't think if you do you'll get the answer you had before
OpenStudy (toxicsugar22):
ok
OpenStudy (toxicsugar22):
vut can u help me get me put that in slope inetcept form
OpenStudy (anonymous):
Well start by distributing the 1/3, then subtract 2 from both sides
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OpenStudy (toxicsugar22):
y+2=1/3(x-4)
can u help me put tis in slpo intecept orm
OpenStudy (toxicsugar22):
can u help me
OpenStudy (anonymous):
did you distribute the 1/3?
OpenStudy (toxicsugar22):
how do u do -4/3-2
OpenStudy (anonymous):
convert -2 into an improper fraction (with a 3 in the denominator)
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OpenStudy (toxicsugar22):
i got y+2=1/3x-4/3
OpenStudy (toxicsugar22):
is that right then i subract 2 from both sides
OpenStudy (anonymous):
yes
OpenStudy (toxicsugar22):
then i get y=1/3x-3.3
OpenStudy (toxicsugar22):
is this write
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OpenStudy (anonymous):
-3.33333 = -10/3
OpenStudy (toxicsugar22):
thanks you so much
OpenStudy (toxicsugar22):
The center of a circle is the point C(2,4), and P(-1,6) is a point on the circle. Find the equation of the line tangent to the circle at the point P.
OpenStudy (toxicsugar22):
can u help with this
OpenStudy (anonymous):
umm.. it's pretty nearly the same problem, just with different numbers
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OpenStudy (toxicsugar22):
ok
OpenStudy (toxicsugar22):
but can u help me
OpenStudy (anonymous):
draw the picture of what they're describing, and recall what we did in this last problem and see if you can figure out how the problems are similar.
OpenStudy (toxicsugar22):
i tried please can u help me
OpenStudy (anonymous):
what did you try?
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OpenStudy (toxicsugar22):
i tried doing it but idid not get it
OpenStudy (toxicsugar22):
doing the pomble
OpenStudy (toxicsugar22):
can u help me
OpenStudy (anonymous):
what did you _do_ when you tried?
OpenStudy (toxicsugar22):
idid (2,4) and (- 1and 6) and added the x and y
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OpenStudy (toxicsugar22):
please can u help, I will be greatful to you
OpenStudy (anonymous):
what were you trying to find when you did that?
OpenStudy (toxicsugar22):
idk i thought that was how u do that
OpenStudy (anonymous):
do what?
OpenStudy (toxicsugar22):
the question
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OpenStudy (anonymous):
Are you trying to find something?
OpenStudy (toxicsugar22):
yes the equation
OpenStudy (anonymous):
the equation of what?
OpenStudy (toxicsugar22):
The center of a circle is the point C(2,4), and P(-1,6) is a point on the circle. Find the equation of the line tangent to the circle at the point P
OpenStudy (anonymous):
I know what the problem says, I'm asking you what you think. You do think right? ;)
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OpenStudy (toxicsugar22):
i am finding it difficult please can u help me
OpenStudy (anonymous):
What are you trying to find here?
OpenStudy (toxicsugar22):
the equation i guess
OpenStudy (anonymous):
The equation of what?
OpenStudy (toxicsugar22):
the slope
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OpenStudy (toxicsugar22):
the slope
OpenStudy (anonymous):
"Find the equation of the line tangent to the circle at the point P"
OpenStudy (anonymous):
What does that sentence mean?
OpenStudy (toxicsugar22):
i think it means that the line is touching line p
OpenStudy (toxicsugar22):
is that right
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OpenStudy (toxicsugar22):
is this righ t
OpenStudy (anonymous):
The line is touching the point P that's on the circle, but what else do you know about it?
OpenStudy (toxicsugar22):
idk
OpenStudy (anonymous):
well, specifically how does it relate to the radius of the circle through the point P?
OpenStudy (toxicsugar22):
is the slope -3/2
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OpenStudy (toxicsugar22):
is it right
OpenStudy (anonymous):
that is the slope of the radius (line between the center and P). The trick is to realize that the slope of the tangent will be perpendicular to the radius.
OpenStudy (toxicsugar22):
so it will be 2/3
OpenStudy (toxicsugar22):
is that right
OpenStudy (anonymous):
that is the slope. now use the point p to find the equation like we did before
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OpenStudy (toxicsugar22):
so we do (-1,-6)
OpenStudy (toxicsugar22):
so it would be y+6=2/3(x+1)
OpenStudy (toxicsugar22):
is that right
OpenStudy (anonymous):
I thought P was (-1,6), so it would be y-6 = 2/3(x+1)
OpenStudy (toxicsugar22):
oh yeah sorry your right
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OpenStudy (toxicsugar22):
if i put it in slope intecept orm it would be y=2/3x+6.67
OpenStudy (toxicsugar22):
is this right
OpenStudy (anonymous):
yeah
OpenStudy (toxicsugar22):
but is the 6.67 right or can i put it in a fraction
OpenStudy (anonymous):
you can make it a fraction
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OpenStudy (toxicsugar22):
how can u show me
OpenStudy (anonymous):
How many 3rds are there in 6 wholes?
OpenStudy (toxicsugar22):
so id it 20/3
OpenStudy (toxicsugar22):
wait i think we messed up it would be y+6=2/3(X-1)
OpenStudy (toxicsugar22):
i think that is right
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OpenStudy (toxicsugar22):
i think that is right
OpenStudy (anonymous):
If the point P is (-1,6) then the equation would be y-6=2/3(x+1)
The formula for point-slope is:
\[y-y_1 = m(x-x_1)\]
Where \(x_1,y_1\) are the x,y values of your point