Question

divide (10-6i)/(2+3i)
a.12/13+42/13i
b.2/13-42/13i
c.5-2i
d.3

Answer 1

\[\frac{10-6i}{2+3i}=\frac{10-6i}{2+3i}\times \frac{10-6i}{2-3i}\]

Answer 2

Multiply the conjugate of the denominator with the numerator and the denominator

Answer 3

denominator is \[2^2+3^2=4+9=13\]

Answer 4

ooops typo my mistake sorry.

Answer 5

2(5-3i) / (2 +3i)

i don't know whats next

Answer 6

\[\frac{10-6i}{2+3i}\times \frac{2-3i}{2-3i}\]

Answer 7

denominator is 13
numerator is \[(10-6i)(2-3i)=2-42i\]

Answer 8

so you get \[\frac{2-42i}{13}=\frac{2}{13}-\frac{42}{13}i\] in standard form

Answer 9

38-41i
-------
13

Answer 10

radar -30-12=-42 i think

Answer 11

Yes, I see that I erred. Lost track of signs lol

Answer 12

and \[-6 \times (-3)=+18\] making the real part 20-18=2

Answer 13

I totally agree satellite, please excuse my mistake Adam12.

Answer 14

Looks like choice B is the best one.