Question

write it in the form of a+ib
(2+3i)(2-i/1+2i)2(whole square)

Answer 1

Not quite sure of your typing. Do you mean (2 + 3i)(2 - i/(1 + 2i))2?

If so, sort out the fraction i/(1 + 2i) first. Multiply top and bottom by the conjugate (1 - 2i), to get (2 + i)/5

The answer I get is (2/5)(19 + 22i), but please check your typing first.

Answer 2

the question is (2+3i) (2-i/1+2i)^2