maximize the objective function p = 3x+y sibject to the following constraints
4x+5y≤9
2x-y≥1
x≥0
y≥0
on my teachers answer sheet ht has 1/2,0 as his corner points
2.25,0 as another
1,1(which is the intersection of the two lines), how did my teacher get the other two corner points?
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OpenStudy (anonymous):
by the simultaneous solution of both lines
OpenStudy (anonymous):
i saw the 1,1 with the intersection but did not find the (2.25,0) and the (1/2,)
OpenStudy (anonymous):
1/2,0 i mean
OpenStudy (anonymous):
both the points lie on x-axis
OpenStudy (anonymous):
mean they are the intersection of lines with x-axis
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OpenStudy (anonymous):
i got the 1,1 intersection using my calculator but the 1/2,0 and 2.25, 0 did not come up. how would i find those?
OpenStudy (anonymous):
\[4x+5y \le 9\]
OpenStudy (anonymous):
x=0
OpenStudy (anonymous):
y=0
OpenStudy (amistre64):
2x-y≥1 is this a typo?
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OpenStudy (anonymous):
\[2x-y \ge 1\]
OpenStudy (anonymous):
thats what my teacher put
OpenStudy (anonymous):
oh i have to write the equtions instead of inequalities
OpenStudy (anonymous):
the answers are y ≤ 9-4x/5 and y ≤ 2x-1
OpenStudy (anonymous):
4x+5y=9
y=0 gives
x=9/4=2.25
point of intersection of the line and x-axis is (2.25,0)
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OpenStudy (anonymous):
likewise for the second eqn
2x-y=1
y=0
x=1/2
point is (1/2,0)
OpenStudy (anonymous):
is the 5 in the deonominator a typo on his part?
OpenStudy (anonymous):
5 in denominator?
OpenStudy (anonymous):
this is how we get the corner points
OpenStudy (anonymous):
on his answer key it says 9-4x/5
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OpenStudy (anonymous):
that makes more sense thanks a lot
OpenStudy (anonymous):
so should i change the answer on the key where it says 9-4x/5?
OpenStudy (anonymous):
is it y=9-4x/5?
OpenStudy (anonymous):
it was originally 4x+5y≤ 9
OpenStudy (anonymous):
fine..what next?
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OpenStudy (anonymous):
to draw the line transform it into eqn
4x+5y=9
OpenStudy (anonymous):
then he has his answer as y ≤ 9-4x/5
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
correct
OpenStudy (anonymous):
what next?
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OpenStudy (anonymous):
the x should then be move to the other side
OpenStudy (anonymous):
the 4x
OpenStudy (anonymous):
which x?actually m not getting you what you actually want
OpenStudy (anonymous):
u are to maximize the objective function subject to some constraints...right?
OpenStudy (anonymous):
thats correct
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OpenStudy (anonymous):
for that u r given two lines and first quadrant
OpenStudy (anonymous):
we draw the lines n mark the feasible region, just like explained in ur previous post
OpenStudy (anonymous):
maximum value liea at one of the corner points
OpenStudy (anonymous):
lies*
OpenStudy (anonymous):
ok that makes more sense
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