Question

Find the exponential function that satisfies the conditions: initial population: 500, doubling every 4.62 days.

Answer 1

let
\[x=x(initial)* e ^{at}\]
where x(initial)=500
to find a,
\[1000=500*e ^{a*4.62}\]
\[a={\ln (1000/500)}/4.62\]
=\[0.15 day ^{-1}\]
so the equation is
\[x=x(initial)*e ^{.15t}\]

Answer 2

gracias!