Question

is anyone good with trigometry??

Answer 1

trigo wat

Answer 2

trigonometric

Answer 3

maybe.

Answer 4

euclid maybe; but hes dead :/

Answer 5

post wht you have

Answer 6

you can use the pythagorean theorem to find b and then use that to find a

Answer 7

this triangle is not possible... your hypotenuse will always be longer than each leg... this is not the case in this picture

Answer 8

b^2 + 13^2 = (12+a)^2

5^2 + a^2 = b^2

Answer 9

what about this?
How long is a string reaching from the top of a 8ft pole to a point 5 ft from the base of the pole?

Answer 10

(12+a)^2 - 13^2 = 5^2 + a^2

Answer 11

looks like similar triangles to me.

Answer 12

I'm trying to study for finals...

Answer 13

144 + a^2 + 24a - 196 = 25 + a^2

144 - 196 - 25 = -24a

144 - 196 - 25 = a
--------------
-24

Answer 14

@amistre64 which one is that for?

Answer 15

a = 77/24..... the first one you posted

Answer 16

how about...
A slide 4.1 m long makes an angle of 28 degrees with the ground. How high is the top of the slide above the ground?

Answer 17

4.1 sin(28)

Answer 18

thats all you do for that?

Answer 19

yes; unless you wanna put it into a calculator to get an approx distance

Answer 20

yeah, that first triangle set up could have been ration

Answer 21

what about
find the missing abgle and side measure of triangle ABC, given that angle A=50 degrees, Angle C= 90 degrees, and CB=7

Answer 22

PEOPLE! it is much easier to solve with similar triangles!
5/13 = a/5 --- > a = 25/13

Answer 23

dhat; yeah, i know :) just thought id give it a shot the other way lol

Answer 24

oh okay. go on. :)

Answer 25

given 2 degrees and a side you can do law of cosines to get another side and then law of sine it with some careful planning

Answer 26

given angles and a side; law of sines might be the best optio

Answer 27

how excatly would i do that.?

Answer 28

never mind that; this is a 90 degree to begin with

ABC, given that angle A=50 degrees, Angle C= 90 degrees, and CB=7

Answer 29

angB = 40

Answer 30

7 AC
----- = ------- tho
sin 50 sin(40)

Answer 31

ac = abt 5.874 maybe

Answer 32

7 ab
----- = ----- = abt 9.12
sin 50 sin90

Answer 33

my two options are;
A) <B=40 degrees, C=9.1, b=5.9
B) <B=40 degrees, C=8.6, b=5.9

Answer 34

the trick is to dbl check that and see how close it is :)

Answer 35

a then

Answer 36

so how'd you get the 7 over sin 50 and the ab over sin90?

Answer 37

thats the law of sines;

side a side b side c
----- = ------ = ------
sin(a) sin(b) sin(c)

Answer 38

7
----- is a given; so the others just fall from that
sin(50)

Answer 39

ohhh okay. My teacher sucked at teaching the law of sines so i can never get it.

Answer 40

cos(g) = a/sqrt(45)

sin^2 + cos ^2 = 1

sin^2 + a^2/45 = 1

sin^2 = 1 - a^2/45

sin = sqrt(1-a^2/45)

tan(g) = sqrt(1-(a^2/45))
---------------
a^2/sqrt(45)

Answer 41

tan(g) = sqrt(1-(a^2/45)) (sqrt(45))
-----------------------
a^2


tan(g) = sqrt(1-(a^2/45)(45))
--------------------
a^2


tan(g) = sqrt(45-a^2)
------------
a^2

Answer 42

How about this.? Thank you for all your help too. If you need anything in return I'd be glad to

Answer 43

x = 23 sqrt(2)
y = 23 + 46cos 30

Answer 44

hey you wrote this: tan(g) = sqrt(45-a^2)
------------
a^2
But how would i finish it.?

Answer 45

With regard to 20110518.13.41.36.jpg:
\[a=5 \text{Cos}\left[\frac{\pi }{2}-\text{ArcTan}\left[\frac{5}{12}\right]\right]=\frac{25}{13} \]\[b=5 \text{Sin}\left[\frac{\pi }{2}-\text{ArcTan}\left[\frac{5}{12}\right]\right]=\frac{60}{13} \]\[\sqrt{\left(\frac{25}{13}\right)^2+\left(\frac{60}{13}\right)^2}=5 \]