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solve equation by taking square roots: k^2+76 how do i do that?
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This is not an equation. In equations, there must be an equality sign.
the plus was supposed to be =, sorrry. k^2=76
if the plus sign was an equals sign: the square root of k^2 is k. so k= sqrt of 76. which is 8.717797887....
But if you're asking about \(k^2+76=0\) then it has no real solution.
OK then, NK got the answer for you :D.
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\[k^2=76 \implies k=-\sqrt{76}, k=\sqrt{76}\]
So two solutions.
so how would you get the answer for k^2=16? ...
K can have two values; \(k=4\) or \(k=-4\)
do you just find the square root of the last number?
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Yep, and take both positive and negative values.
so x2=21 is 4.58.... or no? :(
Exactly \(x=4.58\) or \(x=-4.58\) :)
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