Question

Sheila
use the four-step process to find f'(x) and then f'(1), f'(2) and f'(3).

f(x) = 2x^2+8

Answer 1

Never heard of "the four-step process"!!

Answer 2

i am taking a calculus class and this is in the book. but thanks

Answer 3

\(f'(x)=4x\), so \(f'(1)=4\), \(f'(2)=8\) and \(f'(3)=12\).

Answer 4

can you walk me thru the process?

Answer 5

Well, the derivative of \(x^n\) is \(nx^{n-1}\), and the derivative of a constant is 0. Then just plug the values of 1, 2 and 3 into your derivative.

Answer 6

thanks

Answer 7

You're welcome!