Question

Give the center radius of each equation.Then sketch the graph.
(x-3)square + (y+4)square minus 9=0

Answer 1

\[(x-3)^2+(y+4)^2=9\]
if center = (h,k) and radius = r, then the general form is
\[(x-h)^2+(y-k)^2=r^2\]
Thus center=(3,-4) and r=3

Answer 2

why is 4 negative and 3 positive
and thank so much

Answer 3

because it must be in the form (x-h)^2 and so for (x-h) to equal (x-3), h must be positive 3. Similarly, if (y+4)=(y-k), then k=-4

Answer 4

ok how is this supose to be graphed because im looking at the example of the graph and it very difficult

Answer 5

do you have a compass?

Answer 6

no

Answer 7

well, it's going to be a circle, so I would, starting from (3,-4), go 3 units up, down, left and right.

Answer 8

then draw a curve through those four points by hand and make it as circular as you can?

Answer 9

ok one more question same problem different equation

Answer 10

x square + y square = 36

Answer 11

ok, this one is actually a little simpler. See, to get it in the standard form, all we do is rewrite it as
\[(x-0)^2+(y-0)^2=6^2\]
now clearly it's the same equation as the one you gave me, just a little more convenient

Answer 12

and from this we determine the center is (0,0) and the radius is 6

Answer 13

why is it 6 when you square root it

Answer 14

sorry dumb question

Answer 15

i see lol

Answer 16

that's alright, as long as you understand it now

Answer 17

and if you don't, i'd be happy to answer anything else

Answer 18

man you have been a big help ill be sure to be back on this mabey in a hour or so or minutes thanks :)