Question

(4+radical10)(4-radical10)???
I Actually need steps On How to Do This, Test tomorrow, Please Help

Answer 1

multiply each term in the first by each term in the second.
This gives
\[4*4-4*\sqrt{10}+4*\sqrt{10}-\sqrt{10}^2=16-10=6\]

Answer 2

Do FOIL:
(x-y)(x+y) = x*x +x*y - x*y - y*y = x^2 -y^2
If x = 4 & y = radical 10
The answer is 4^2 -(radical 10)^2 = 16-10 = 6

Answer 3

What The Monkey Is FOIL?

Answer 4

http://www.algebrahelp.com/lessons/simplifying/foilmethod/

Answer 5

First items in the brackets
Outside items in the brackets
Inside items in the brackets
Last items in the brackets....its a way to remember how to expand the equation

Answer 6

The sqrt x+c * sqrt x-c ...that has a name....anyone recall what it is?

Answer 7

What are you talking about: difference of squares?

Answer 8

nope the square root version has its own name...

Answer 9

nonsense. \[(a+b)(a-b)=a^2-b^2\]
\[(4+\sqrt{10})(4-\sqrt{10})=4^2-\sqrt{10}^2=16-10=6\]

Answer 10

'foil' is a trick math teachers play on students.

Answer 11

conjugate...there it is sqrt x+c is the conjugate of sqrt x-c....probably the same for squares but it never came up. And I recall it coming up for complex numbers too now that I found it. i+c and i-c used to get rid of the complex number. =)