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What are the asypmtotes of the hyperbola (x-1)^(2)/(25)-(y-4)^(2)/(16)= ?
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In general the asymptotes of a hyperbola are y = (b/a) and y = - (b/a).
sorry they are y=+/-(b/a)x
5y=24-4x and 5y=4x+16
Where did you come up with that equation?
y=(b/a)x and y=-(b/a)x are the asymptotes the the "general" hyperbola
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but where did you pull the numbers from?
y-4=+/-(4/5)(x-1)
is that the answer?
yes.
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