Question

Solve for x. 9^(x+8) = 17^(7x)
using log base 10?

Answer 1

a start is
\[log(9^{x+8})=log(17^{7x})\]
\[(x+8)log(9)=7xlog(17)\]

Answer 2

remember that \[log(9)\] and \[log(17)\] are just numbers (constants) so it is algebra from there on in. multiply out etc to solve for x.

Answer 3

\[xlog(9) + 8log(9)=7xlog(17)\]
\[8log(9) = 7xlog(17)-xlog(9)\]
\[8log(9)=x(7log(17)-log(9))\]
\[x=\frac{8log(9)}{7log(17)-log(9)}\]

Answer 4

and how do you find like what log(9) is ?

Answer 5

use your calculator at this point