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Mathematics 17 Online
OpenStudy (anonymous):

need help with limit graph and q's

OpenStudy (anonymous):

can you see it

OpenStudy (anonymous):

a) = -1 b = 2

OpenStudy (anonymous):

hmmm I don't think that is right a or b

OpenStudy (anonymous):

what do you think it is

OpenStudy (anonymous):

limit is asking what is the y value as x gets closer to -3 ...a) is asking what is y becoming as x turns into three from the left side. That arrow is definitely not pointing to -1. b) is asking the same thing from the right side that arrow is not pointing at 2.

OpenStudy (anonymous):

x turns to negative 3

OpenStudy (anonymous):

so it should be -1 right?

OpenStudy (anonymous):

-3 looks like a vertical asymptote to me...which x=-3 are you looking at? maybe the graph you posted and the one im seeing are different?

OpenStudy (anonymous):

oooh my mistake

OpenStudy (anonymous):

so - inf

OpenStudy (anonymous):

for a)

OpenStudy (anonymous):

3 for b?

OpenStudy (anonymous):

yes but depending on how your teacher/book are looking at it they may say that the limit is undefined too if you start at x = 0 and move left towards x=-3 what happens to the line with the arrow?

OpenStudy (anonymous):

yeah undefined also

OpenStudy (anonymous):

=) that one is heading to +oo

OpenStudy (anonymous):

so I know you have c) nailed

OpenStudy (anonymous):

and d) for that matter

OpenStudy (anonymous):

c = DNE

OpenStudy (anonymous):

and neg inf

OpenStudy (anonymous):

d = 3

OpenStudy (anonymous):

oh so close....c) is saying if you approach from either direction...so it is + and - infinity depending which side of the line you are on....so undefined probably best. for d) what is y when x=-3?

OpenStudy (anonymous):

d = 3 right

OpenStudy (anonymous):

no =) the arrowy lines don't point at 3 they point at? -oo and +oo.....so .......undefined the lines dont cross x=-3 at all

OpenStudy (anonymous):

alright the next few are tough

OpenStudy (anonymous):

is it all .5?

OpenStudy (anonymous):

e-h

OpenStudy (anonymous):

uh oh I thought there were getting easier... all good

OpenStudy (anonymous):

i - L have a trick to them

OpenStudy (anonymous):

wait so e- h = .5 right?

OpenStudy (anonymous):

indeed you are correct

OpenStudy (anonymous):

cool

OpenStudy (anonymous):

i = 1

OpenStudy (anonymous):

f = 1

OpenStudy (anonymous):

it is always easier when the limits exist i=1 is correct

OpenStudy (anonymous):

well j anyway =)

OpenStudy (anonymous):

right haha

OpenStudy (anonymous):

k also 1

OpenStudy (anonymous):

you on a roll now

OpenStudy (anonymous):

j = dne

OpenStudy (anonymous):

woot

OpenStudy (amistre64):

j should exist; its a onesided limit

OpenStudy (anonymous):

nah it cant its asking for the value at f(0)

OpenStudy (anonymous):

oh right yeah

OpenStudy (amistre64):

j. lim{x ->0+} = ?? its goes to 1

OpenStudy (anonymous):

lets move onto m

OpenStudy (anonymous):

aaak i didnt pay attention to you going back to j I read that as an L

OpenStudy (anonymous):

yep we already got that

OpenStudy (anonymous):

yep me 2

OpenStudy (anonymous):

okies I am at M

OpenStudy (anonymous):

m = 4?

OpenStudy (anonymous):

f = 4

OpenStudy (anonymous):

sorry n = 4

OpenStudy (amistre64):

m=5 if the graph is right

OpenStudy (anonymous):

m != 4 keep in mind the axis are in a funny spot

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

x=1 looks a lot like that vertical asymptote at -3 to me

OpenStudy (anonymous):

m-p = 4

OpenStudy (anonymous):

I think you are looking at the wrong x=1

OpenStudy (anonymous):

oh hi mistre!

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

m= - inf

OpenStudy (anonymous):

I think so too

OpenStudy (anonymous):

n = - inf

OpenStudy (anonymous):

now we back on track

OpenStudy (anonymous):

o = - inf

OpenStudy (anonymous):

o. oh oh yeah

OpenStudy (anonymous):

and p = dne

OpenStudy (anonymous):

=) you got it now

OpenStudy (anonymous):

only q 2 p 2 go

OpenStudy (anonymous):

q = - .5

OpenStudy (anonymous):

or maybe that should be a t who built this chart anyway?

OpenStudy (anonymous):

r = -.5

OpenStudy (anonymous):

yeah really weird graph

OpenStudy (anonymous):

I buy q=-.5 and r too for that matter

OpenStudy (anonymous):

s = -.5

OpenStudy (anonymous):

yay

OpenStudy (anonymous):

q as well -.5

OpenStudy (anonymous):

t) i mean

OpenStudy (anonymous):

ding you have reached the next level....hehe alphabetically challenged homework

OpenStudy (anonymous):

new graph hold on second

OpenStudy (anonymous):

do you see it

OpenStudy (anonymous):

limx→2+f(x) =5≠limx→2−f(x)=2

OpenStudy (anonymous):

let me print it out standby

OpenStudy (anonymous):

we need 4 answers

OpenStudy (anonymous):

and im playing world of warcraft too....semester ended monday for me =)

OpenStudy (anonymous):

haha

OpenStudy (anonymous):

are you in hs or college?

OpenStudy (anonymous):

college...again ....

OpenStudy (anonymous):

nice pass time hit the ladies up instead ;)

OpenStudy (anonymous):

but what would my wife think?

OpenStudy (anonymous):

ah never mind then

OpenStudy (anonymous):

f(2) exists (infact f(2) = 4

OpenStudy (anonymous):

we need 4 answers

OpenStudy (anonymous):

f(x) is continuous at 2 i think jump continutity

OpenStudy (anonymous):

so far a)f(x) is continuous at 2 i think jump continutity b) f(2) exists (infact f(2) = 4 c) f(2) = limit x->2 F(x)

OpenStudy (anonymous):

jump continuity is the opposite of continuous though

OpenStudy (anonymous):

so is it continuous?

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