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OpenStudy (anonymous):
can you see it
OpenStudy (anonymous):
a) = -1
b = 2
OpenStudy (anonymous):
hmmm I don't think that is right a or b
OpenStudy (anonymous):
what do you think it is
OpenStudy (anonymous):
limit is asking what is the y value as x gets closer to -3 ...a) is asking what is y becoming as x turns into three from the left side. That arrow is definitely not pointing to -1. b) is asking the same thing from the right side that arrow is not pointing at 2.
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OpenStudy (anonymous):
x turns to negative 3
OpenStudy (anonymous):
so it should be -1 right?
OpenStudy (anonymous):
-3 looks like a vertical asymptote to me...which x=-3 are you looking at? maybe the graph you posted and the one im seeing are different?
OpenStudy (anonymous):
oooh my mistake
OpenStudy (anonymous):
so - inf
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OpenStudy (anonymous):
for a)
OpenStudy (anonymous):
3 for b?
OpenStudy (anonymous):
yes but depending on how your teacher/book are looking at it they may say that the limit is undefined too
if you start at x = 0 and move left towards x=-3 what happens to the line with the arrow?
OpenStudy (anonymous):
yeah undefined also
OpenStudy (anonymous):
=) that one is heading to +oo
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OpenStudy (anonymous):
so I know you have c) nailed
OpenStudy (anonymous):
and d) for that matter
OpenStudy (anonymous):
c = DNE
OpenStudy (anonymous):
and neg inf
OpenStudy (anonymous):
d = 3
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OpenStudy (anonymous):
oh so close....c) is saying if you approach from either direction...so it is + and - infinity depending which side of the line you are on....so undefined probably best.
for d) what is y when x=-3?
OpenStudy (anonymous):
d = 3 right
OpenStudy (anonymous):
no =) the arrowy lines don't point at 3 they point at?
-oo and +oo.....so .......undefined the lines dont cross x=-3 at all
OpenStudy (anonymous):
alright the next few are tough
OpenStudy (anonymous):
is it all .5?
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OpenStudy (anonymous):
e-h
OpenStudy (anonymous):
uh oh I thought there were getting easier...
all good
OpenStudy (anonymous):
i - L have a trick to them
OpenStudy (anonymous):
wait so e- h = .5 right?
OpenStudy (anonymous):
indeed you are correct
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OpenStudy (anonymous):
cool
OpenStudy (anonymous):
i = 1
OpenStudy (anonymous):
f = 1
OpenStudy (anonymous):
it is always easier when the limits exist
i=1 is correct
OpenStudy (anonymous):
well j anyway =)
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OpenStudy (anonymous):
right haha
OpenStudy (anonymous):
k also 1
OpenStudy (anonymous):
you on a roll now
OpenStudy (anonymous):
j = dne
OpenStudy (anonymous):
woot
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OpenStudy (amistre64):
j should exist; its a onesided limit
OpenStudy (anonymous):
nah it cant its asking for the value at f(0)
OpenStudy (anonymous):
oh right yeah
OpenStudy (amistre64):
j. lim{x ->0+} = ?? its goes to 1
OpenStudy (anonymous):
lets move onto m
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OpenStudy (anonymous):
aaak i didnt pay attention to you going back to j I read that as an L
OpenStudy (anonymous):
yep we already got that
OpenStudy (anonymous):
yep me 2
OpenStudy (anonymous):
okies I am at M
OpenStudy (anonymous):
m = 4?
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OpenStudy (anonymous):
f = 4
OpenStudy (anonymous):
sorry n = 4
OpenStudy (amistre64):
m=5 if the graph is right
OpenStudy (anonymous):
m != 4 keep in mind the axis are in a funny spot
OpenStudy (anonymous):
yeah
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OpenStudy (anonymous):
x=1 looks a lot like that vertical asymptote at -3 to me
OpenStudy (anonymous):
m-p = 4
OpenStudy (anonymous):
I think you are looking at the wrong x=1
OpenStudy (anonymous):
oh hi mistre!
OpenStudy (anonymous):
yep
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OpenStudy (anonymous):
m= - inf
OpenStudy (anonymous):
I think so too
OpenStudy (anonymous):
n = - inf
OpenStudy (anonymous):
now we back on track
OpenStudy (anonymous):
o = - inf
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OpenStudy (anonymous):
o. oh oh yeah
OpenStudy (anonymous):
and p = dne
OpenStudy (anonymous):
=) you got it now
OpenStudy (anonymous):
only q 2 p 2 go
OpenStudy (anonymous):
q = - .5
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OpenStudy (anonymous):
or maybe that should be a t who built this chart anyway?
OpenStudy (anonymous):
r = -.5
OpenStudy (anonymous):
yeah really weird graph
OpenStudy (anonymous):
I buy q=-.5 and r too for that matter
OpenStudy (anonymous):
s = -.5
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OpenStudy (anonymous):
yay
OpenStudy (anonymous):
q as well -.5
OpenStudy (anonymous):
t) i mean
OpenStudy (anonymous):
ding you have reached the next level....hehe alphabetically challenged homework
OpenStudy (anonymous):
new graph hold on second
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OpenStudy (anonymous):
do you see it
OpenStudy (anonymous):
limx→2+f(x) =5≠limx→2−f(x)=2
OpenStudy (anonymous):
let me print it out standby
OpenStudy (anonymous):
we need 4 answers
OpenStudy (anonymous):
and im playing world of warcraft too....semester ended monday for me =)
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OpenStudy (anonymous):
haha
OpenStudy (anonymous):
are you in hs or college?
OpenStudy (anonymous):
college...again ....
OpenStudy (anonymous):
nice pass time hit the ladies up instead ;)
OpenStudy (anonymous):
but what would my wife think?
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OpenStudy (anonymous):
ah never mind then
OpenStudy (anonymous):
f(2) exists (infact f(2) = 4
OpenStudy (anonymous):
we need 4 answers
OpenStudy (anonymous):
f(x) is continuous at 2 i think jump continutity
OpenStudy (anonymous):
so far
a)f(x) is continuous at 2 i think jump continutity
b) f(2) exists (infact f(2) = 4
c) f(2) = limit x->2 F(x)
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OpenStudy (anonymous):
jump continuity is the opposite of continuous though