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Mathematics 9 Online
OpenStudy (anonymous):

2 l -x+4 l > 10 solve for X

OpenStudy (anonymous):

6l-10>x

OpenStudy (anonymous):

theres arent ls haha sorry those are absolute values

OpenStudy (anonymous):

those*

OpenStudy (anonymous):

oh :D

OpenStudy (anonymous):

if you could tell me how to do it that be great i now i have to divide by 2.... but does that change the signn.

OpenStudy (anonymous):

yes that is the first step. no it does not change the sign

OpenStudy (anonymous):

than you have to divide it to two parts. when x>= 4 than the absolute value does nothing so you get -x+4 >5 -1>x this is contradiction as x cannot be bigger than 4 and smaller than -1 at the same time

OpenStudy (anonymous):

whered you get negative one the -x will become positive so i wouldnt have to divide right..? then i would have to do this problem again with flipping the sign and negating the 10

OpenStudy (anonymous):

the second part is when 4>=x than the absolute value multiplies it by -1 so you get x-4>5 x>9 this is another contradiction so I must have done something wrong :) time to double check

OpenStudy (anonymous):

try this: \[|-x+1|=|1-x|=|x-1|\] now you don't have that annoying minus sign in front of the x. \[2|x-1|>10\] \[|x-1|>5\] \[x-1>5\]or \[x-1<-5\]

OpenStudy (anonymous):

there is no contradiction. you have two easy inequalities to solve.

OpenStudy (anonymous):

Satellite that answer is incorrect this is a muiltiple choice question and the only answers are with 1 and 9 ... there was no need to move the -x when its in an absolute value sign the - drops anyway which is where the problem may be with your solution

OpenStudy (anonymous):

sat it is not -x+1 but -x+4

OpenStudy (anonymous):

Hahah thanks Andras that could be the problem as well haha

OpenStudy (anonymous):

oops i read it as \[-x+1\] not \[-x+4\] i apologize.

OpenStudy (anonymous):

yeah the answer should be x>9 or -1>x

OpenStudy (anonymous):

sorry. messed up by not reading carefully.

OpenStudy (anonymous):

the choices are 1<x<9 (x<1) or (x>9) (x<-9) or (x>-1) (x<-1)or(x>9)

OpenStudy (anonymous):

(x<-1)or(x>9)

OpenStudy (anonymous):

ok thanss both for the help :]

OpenStudy (anonymous):

thanks*

OpenStudy (anonymous):

\[21-x+41>10\] Collect like terms on RHS \[62-x >10\] Subtract 10 from both sides; \[52-x >0\] Add x to both sides \[52>x\] That is;\[x <52\]

OpenStudy (anonymous):

Those are absolute values... not 1..

OpenStudy (anonymous):

i got the answer already :]..

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