lim x→−3 6x + 18/|x + 3|
i got 6 but i think its wrong
the top factors to cancel the bootom
6 is right
but what about the absolute value signs
6(x+3) ------ hmm, i think they are the same as a + value here |x+3|
i thought i had to do -x-3, and x+3
http://www.wolframalpha.com/input/?i=lim {x+to+-3}%28%286x%2B18%29%2F%28|x%2B3|%29%29
http://www.wolframalpha.com/input/?i=lim {x+to+-3}%28%286x%2B18%29%2F%28|x%2B3|%29%29
it cuts the link short...
i see it tho... the limit doesnt exist it says
since the limit is not the same form left and right; no limit exists
okay thanks
those absolutes getcha i fyou dont watch for em
yeah im doing like 40 problems of nothing put absolutes
lol.. good for the practice :)
haha yeah i guess
if you factor it to get the same looking stuff; it tends to wanna break apart at the '0' limit if thats what they are going for
lim x->-7 (7 - (abs of (x))/(7 + x) is this DNE
7 - |x| ------ right? 7+x
yeah
lets see what this does a little bit to the left and right of -7 then
-6.9; what doe we get?
1
ok.. and at 7.1?
-7.1 that is
1
so its 1
thats a good sign; try with smaller numbers to be sure; -6.9999 and -7.0001
the answer is 1 :)
okay that seems much easier than doing it the way my professor said
if the limit on the left and right are the same; then you have the limit; if they differ, no limit ewxists
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