Question

need help with continuity of limits graph posted

Answer 1

top one is question below one is example

Answer 2

hello

Answer 3

It seems you didn't understand what I said earlier :).
All the limits and f(2)=4 in this case. So the function is continuous.

Answer 4

well here are the tougher q's i dont know if she wants us to graph or not

Answer 5

4. Find where the Functions are discontinuous.
a. F(x) = x + 3/ x2 – 9
b. F(x) = x + 6/ x2 + 36
c. F(x) = 3x - 6

Answer 6

Well you can try by sketching the graphs and see where the function has a hole, jump or asymptote.

Answer 7

i was thinking factoring the denominator

Answer 8

for a)

Answer 9

yes that's good

Answer 10

then it comes out to 0/x-3

Answer 11

i am horrible at math i will admit i dont know what to do next

Answer 12

when you factor you have \(\frac{x+3}{(x+3)(x-3)}\). Remember we can't divide by zero. So the function is undefined at x=-3 and x=3. Then at those points the function is discontinuous.

Answer 13

F(x) = x + 6/ x2 + 36 so for this its at x+6 and x-6

Answer 14

so at 6 and -6

Answer 15

But if you plug in x=-6 or 6 to x^2+6 you won't get zero.

Answer 16

wait its x^2 + 6

Answer 17

so graph is continous eveywhere

Answer 18

yes

Answer 19

its a straight line

Answer 20

good

Answer 21

F(x) = 3x - 6

Answer 22

same with this one?

Answer 23

yup

Answer 24

have a good one bro