Question

How do you find all the real solutions to
x^3-13x-12=0?

Answer 1

wait one moment

Answer 2

\[x \approx4 ; x \approx-3 ; x \approx-1\]

Answer 3

I was a bit complicated

Answer 4

was rectified and that is the correct answer

Answer 5

What about x^4-14x^2+45=0?

Answer 6

wait one moment

Answer 7

factor
(x^2 -5)(x^2 -9)=0
x^2 = 5
x^2 = 9

Answer 8

x=3
x=-3
x=square root(5)
x=-square root(5)

Answer 9

\[\sqrt{5}\approx 2.23 ; -\sqrt{5}\approx - 2.23\]

Answer 10

Could you still factor it if the 14x^2 was 14x^3(in the same problem)?

Answer 11

wait one moment

Answer 12

is very complicated

Answer 13

wait one moment

Answer 14

Don't worry about it then. I was just wondering if they could be only one power different or if they could also be two powers away from each other.

Answer 15

solve this equation is very long process and I think I'm doing that I have out there in 10%

Answer 16

expected and it started to let me finish lol

Answer 17

Can you show me the steps to the x^4-7x^3=0 problem? i think I know how to get 7 but I don't know how you got sero as an answer.

Answer 18

only by deduction. in looking for possible solutions when the right side of the expression as a result of 0 in this case is very easy to see that 7 is the only number other than 0 that satisfies this condition and so that the other three answers are 0 and which is a 4-degree equation must give 4 answers

Answer 19

Okay, so you get x^3(x-7)=0 and solve the two pieces for the answers?

Answer 20

( x^3 ) (x-7)= 0 ??????

Answer 21

I think that is how I was taught it. Then you get x=7 and x^3 =0