x^3+1/x^2-1 * 3x-3/x^3-x^2+x Perform the indicated operations and reduce to the lowest terms, simplify each expression. Can someone please help me! I have a test tomorrow :/
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OpenStudy (stacey):
Do you know how to factor those expressions?
OpenStudy (anonymous):
Um I know x^2-1 = (x+1)(x-1) right?
OpenStudy (anonymous):
Before we start answering your question, is this the expression you have?
\[(x^{3} + 1)/(x^{2} - 1) * (3x - 3) / (x{3} - x^{2}+x) \]
OpenStudy (anonymous):
yes :)
OpenStudy (stacey):
Since x^3 + 1 is a sum of cubes it factors into
(x+1)(x^2 - x + 1)
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OpenStudy (anonymous):
and then below that I would put (x+1)(x-1) right
OpenStudy (stacey):
Correct.
For the second fraction, the numerator can be factored by taking out the common factor of 3 and the denominator can be factored by taking out the common factor of x.
OpenStudy (anonymous):
Oh so then it would be 3(x-1) / x(x^2-x+1) ? or do I not put the 1
OpenStudy (stacey):
You have it correct.
OpenStudy (anonymous):
Yay! Do you have time for another question?
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OpenStudy (anonymous):
wait everything cancelled?
OpenStudy (stacey):
Not quite everything.
OpenStudy (stacey):
You should still have a 3 in the numerator and an x in the denominator.
OpenStudy (anonymous):
Oh yeah I totally ignored that. So my answer would be 3/X
OpenStudy (stacey):
Yes
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