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Mathematics 23 Online
OpenStudy (anonymous):

x^3+1/x^2-1 * 3x-3/x^3-x^2+x Perform the indicated operations and reduce to the lowest terms, simplify each expression. Can someone please help me! I have a test tomorrow :/

OpenStudy (stacey):

Do you know how to factor those expressions?

OpenStudy (anonymous):

Um I know x^2-1 = (x+1)(x-1) right?

OpenStudy (anonymous):

Before we start answering your question, is this the expression you have? \[(x^{3} + 1)/(x^{2} - 1) * (3x - 3) / (x{3} - x^{2}+x) \]

OpenStudy (anonymous):

yes :)

OpenStudy (stacey):

Since x^3 + 1 is a sum of cubes it factors into (x+1)(x^2 - x + 1)

OpenStudy (anonymous):

and then below that I would put (x+1)(x-1) right

OpenStudy (stacey):

Correct. For the second fraction, the numerator can be factored by taking out the common factor of 3 and the denominator can be factored by taking out the common factor of x.

OpenStudy (anonymous):

Oh so then it would be 3(x-1) / x(x^2-x+1) ? or do I not put the 1

OpenStudy (stacey):

You have it correct.

OpenStudy (anonymous):

Yay! Do you have time for another question?

OpenStudy (anonymous):

wait everything cancelled?

OpenStudy (stacey):

Not quite everything.

OpenStudy (stacey):

You should still have a 3 in the numerator and an x in the denominator.

OpenStudy (anonymous):

Oh yeah I totally ignored that. So my answer would be 3/X

OpenStudy (stacey):

Yes

OpenStudy (anonymous):

Thank you

OpenStudy (stacey):

You're welcome.

OpenStudy (anonymous):

I have another question?

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