The probability of an event occurring is 23/50. What are the odds that the event will occur?
if the probability in favor is p, then the odds in favor are \[\frac{p}{1-p}\] i.e. probabilty in favor divided by the probability against. in this case you get \[\frac{23}{27}\]
think of it easy as 23 out of 50 chances to win and therefore 27 out of 50 to lose.
the odds are 46%
23/50 that it occurs. the odds that it WILL occur are 46% right?
really? in that case i made a mistake, but i don't think so.
oh no that is probability, not odds.
ahhh... like saying 5 to 2 or something right?
if the probability i win is \frac{2}{3}\] then the odds i win are two to one.
\[\frac{p}{1-p}\]
chance occur to chance not occur is an odd then right?
right like saying 5 to 2. exactly
yes right.
not really used much in math, but sometimes. gamblers' ruin problem. used mostly at the track.
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