Question

Integral of x^5*ln(3x)dx

Answer 1

\(u=\ln(3x)\) and \(dv=x^5\,dx\)
Then \(du=dx/x and v=x^6/6\)
It follows your integral equals
\(=x^6\ln(3x)/6-\int x^5/6\, dx\)
\(=x^6\ln(3x)/6-x^6/36 +C\)

Answer 2

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