find the volume of the solid obtained by rotating the region lying between the curves around the y-axis.
y=sinx
y=e^x
x=pi/2
x=pi

Question

find the volume of the solid obtained by rotating the region lying between the curves around the y-axis. 
y=sinx
y=e^x
x=pi/2
x=pi

watchmath · Answer

$\int_{\pi/2}^{\pi }2\pi x(e^x-\sin x)\,dx$

anonymous · Answer

can you help me with the steps?

amistre64 · Answer

the graph doesnt makes sense ......

amistre64 · Answer

you appear to have a boundary between boundaries

amistre64 · Answer

or, that means that you spin it around the y axis; the part that is between ..got it

amistre64 · Answer

attachment

amistre64 · Answer

if so; shelling is fine;

2pi {S} (xe^x - xsin(x)) dx ; [pi/2, pi]

amistre64 · Answer

but it might be uglier than the disc method to integrate

amistre64 · Answer

e^x =y

x = ln(y); is ln^2(y) easy to integrate?  havent tried it meself lol

amistre64 · Answer

amistre64 · Answer

thnx :)

anonymous · Answer

i have couple more review questions can you help me amistre64?

amistre64 · Answer

i can...maybe