how do you integrate (x^9)(cos(x^5))?

Question

anonymous · Answer

$$intx ^{9}cosx ^{5}dx. $$

anonymous · Answer

Possibly integration by parts

anonymous · Answer

i realize that, but should i don't know what values to assign for u and dv. should i substitute before i even use integration by parts?

anonymous · Answer

Try x^9 as u

anonymous · Answer

((x^10)/10)(-sinx(x^5))

anonymous · Answer

What is that Nick, like the teacher says, show your work.

anonymous · Answer

okay
Integrate (x^9)we get
(x^9+1)/(9+1)
intregrate cos(x^5) we get 
-sin(x^5)

anonymous · Answer

But there is a rule, the two x quantities are multiplied, so you can't integrate straight out, right?

anonymous · Answer

yeah, so you integrate by parts.

anonymous · Answer

yes

anonymous · Answer

substituting u for x^9 doesn't seem to work chaguanas
...

anonymous · Answer

Check this I haven't done integration by parts in a while$$x ^{9}\cos x ^{5}-45x ^{5}\sin x ^{5}$$

anonymous · Answer

+C

watchmath · Answer

watchmath · Answer

wolframalpha will give you the steps as well.

anonymous · Answer

hold on are you sure that the integral of cos x^5 is is -sin x^5 - try differentiating 
-sin x^5.

anonymous · Answer

Yeah, mine is wrong, see the wolfram watchmath put up. That was the u sub that ecollison was talking about, I missed that.

anonymous · Answer

watchmath thanks! the link was right

anonymous · Answer

But please explain the u sub, they didn't account for the x^9 fully.

anonymous · Answer

u=x^5 not x^9

anonymous · Answer

lols