This question has to do with z-scores... A dean must distribute salary raises to her faculty for next year. She has decided that the mean raise is to be $2000, the standard deviation of raises is to be $400, and the distribution is to be normal. She will attempt to distribute these raises on the basis of merit, meaning that people whose performance is better get better raises. The 5% of the faculty who have done nothing useful in years will receive no more than $ _________ each.
ahhhh.... standard deviations eh.... where my ti-83 at?
since it is population; we use mu and such right?
yes
but somehow i need to get a z value or an x value for z=x-mean/sd
2 standards are within the normal right? 95%......
yup
z = x-mu/omega omega = sqrt(n.p.q) right? and mu=n.p
huh? the standard deviation is already given and so is the mean :S
lol...ok; then mu = 2000 and omega then is 400 right?
yup
and the 5% is the smaller portion of the distribution. but I don't know how to if its the z score that gives you the 0.05 or if its something else
use empiraical rule? gotta similar problem here where sd and mean are given
2000 + 400 is one deviation 2000 + 800 is 2 deviations 2000 + 1200 is 3 deviations right?
those in the out liers are more than 2 standards so they get a raise of 2000 - 1200 = 800 right?
make sense?
yes i think so
<.......-2 sd ........ -1 sd..........mean .........etc
yup
might of gone to far in that but you get the basic premise right?
lol yea
good :) we just went over that in stats class yesterday :)
sweet, so do you have a z table with you?
i got some stuff in my stats book; that might help
table a-2; standard deviation (z) distribution
i have multiple choice answers if it makes a difference. a) 1000, b) 1980, c) 1340 and d)2192 it can't be over 2000 so its one of the first 3 choices :S
ahh hate stats!
c looks plausible, but cant really say for sure....
2000 - 2(400) = 1200; but thats just an educated guess...
id have to look up how to use a z table to be sure
well to my understanding, if the 5% is in the smaller portion of the distribution, then you look up0.05 there and get the z score. then just stick that value int he equation and solve for x but its not working
95% falls at the 2 line; and that result is .4772; or 47.72% at most 2000*.4772 = answer maybe? ....954.4 that dint work
.02275 is what that gives me
thanks!
what to do with it I aint got a clue lol
hmm it won't let me put the 0.5 anywhere though just keeps saying 0.0000
lol me either.
i put in the mean 2000 the sd 400 and choose below 1200 for the 5%
i got a 1342 on the bottom part of it lol
yea i got that too but i dont really know what it means lol
i think it means pick c :)
lol okay. wth! its only one question haha thank you sooooo much for your help!!
:) hope we are right ;)
me too :D
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