find the cartesian equation of r = 8 sin thet + 8 cos theta
its a circle centered at the irigin of radius 8 maybe?
\[r =\sqrt{x ^{2}+y ^{2}}\]
polars and parametrics aint my strong point ;)
youre good at vectors :)
yep, I can point at things all day lol
haha, and good at planes
maybe youre good at visualizing things?
im pretty good at visualizing stuff
ok we can use x = r cos theta, and y = r sin theta,
so multiply both sides by r
spinning polars tho.....not so much; aint had the practice
\[\sin \theta =x/r\]
ive read the vector stuff, it just wont stick. for some reason
polars are just vector equations at heart :)
i dont see that
r = magnitude; <cos,sin> are the components
r<cos(t),sin(t)> is the basi set up
those are the cartesian components you mean
in the plane, yes
but polars define length(r) whih is the magnitude of a vector; and the <cos,sin> angles are the x and y components of a vector
a vector function simply defines a curve or surface generated by the parametric equations for the vector components from teh origin
and that is all a polar equation is
come again, parametric equation for the vector components (the cartesian components?)
(r,t) is a polar equation right? (radius,theta) this tells you how far to turn and how far to move
thats all a vector is; an arrow indicating direction and length
ok , lets use th for theta
ok , so say again your statement
which one lol
r<cos(th),sin(th)> is the vector equivalent of a polar equation (r,th)
or simpy <r cos(th), r sin(th)>
vector , as in the cartesian components of the vector
yes
the point P(x,y) is the same as defining a vector from the origin as <x,y>
the vector is an arrow pointing to the point
right, that sometimes confuses me
we write < x,y> for a vector, and P(x,y) for a point
sometimes they write a vector as v(x,y) which confuses tha tmatter; i prefer the convention of just making it pointy to indicate its an arrow :)
right, i like to distinguish between points (n tuples) and vectors
cantorset i posted a proof for your viewing sorry it took me awhile to respond
i cant find it, one sec
k
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