Question

A particle moves under a hypothetical force so that its velocity vector is v= . Find its radial acceleration...Please help...

Answer 1

whata hard bout that?

Answer 2

acceleration is the derivative of velocity with respect to time

Answer 3

assuming k is a constant

Answer 4

\[a = < k \frac{d}{dt} ( tcos(t)) , k \frac{d}{dt} ( tsin(t) ) > \]

Answer 5

k can be factored out of the vector, and it will just provide a scalar multiple

Answer 6

\[a = k < ( \cos(t) -tsin(t)) , (\sin(t) + tcos(t)) > \]

Answer 7

by product rules

Answer 8

wow you are such a genius. I admire you all

Answer 9

?

Answer 10

bt i need the radial accn, not the total accn....

Answer 11

at time t=0

Answer 12

yeh i dnt have clue on that


:|

Answer 13

radial is apparently equal to centripetal= v^2 / r

Answer 14

but i dont have a clue

Answer 15

hey i got it neway ..thnx

Answer 16

\[\vec{a}_n=<-kt\sin{t},kt\cos{t}>\]