A particle moves under a hypothetical force so that its velocity vector is v= . Find its radial acceleration...Please help...

Question

A particle moves under a hypothetical force so that its velocity vector is v= <ktcost, ktsint>. Find its radial acceleration...Please help...

anonymous · Answer

whata hard bout that?

anonymous · Answer

acceleration is the derivative of velocity with respect to time

anonymous · Answer

assuming k is a constant

anonymous · Answer

$$a = < k \frac{d}{dt} ( tcos(t)) , k \frac{d}{dt} ( tsin(t) ) > $$

anonymous · Answer

k can be factored out of the vector, and it will just provide a scalar multiple

anonymous · Answer

$$a = k < ( \cos(t) -tsin(t)) , (\sin(t) + tcos(t)) > $$

anonymous · Answer

by product rules

anonymous · Answer

wow you are such a genius. I admire you all

anonymous · Answer

?

anonymous · Answer

bt i need the radial accn, not the total accn....

anonymous · Answer

at time t=0

anonymous · Answer

yeh i dnt have clue on that


:|

anonymous · Answer

radial is apparently equal to centripetal= v^2 / r

anonymous · Answer

but i dont have a clue

anonymous · Answer

hey i got it neway ..thnx

nikvist · Answer

$$\vec{a}_n=<-kt\sin{t},kt\cos{t}>$$