A spring in, when not taut, has length 10cm. suppose it takes 1kg m/sec^2 to compress the spring 1cm. What is the work required to stretch the spring 3cm?

Question

amistre64 · Answer

W = F*d ; We integrate this somehow, gonna have to refresh meself on it tho

amistre64 · Answer

{S} f(x) dx  where f(x) = hookes law; kx

amistre64 · Answer

k = 1kg and x = 1 cm; so ....still reading up on it lol

amistre64 · Answer

oy its been awhile ..... 1000 kg m/sec^2 = k(.01m) maybe?

amistre64 · Answer

k = 100 kg/sec^2 then i think

amistre64 · Answer

the int this 100x (kg m/sec^2) from 0 to .03 m

amistre64 · Answer

100x^2
------- = 50x^2 at x=.03
    2

50*.0009 = .045  maybe... I aint got the textbook with me to be sure :)

anonymous · Answer

i will make sure to double check with the t/b thanks amistre64 you are a big help! :)

amistre64 · Answer

youre welcome :)  it sounds right, but I just cant be sure ...its been to long since I tried doing spring calculus lol