Question

how do i find the vertex of a function?

Answer 1

If it's a parabola of the form \[ax ^{2} + bx + c \] then the vertex is given by -b/2a

Answer 2

You don't find the vertex of a function, per se, you find the vertex of something, like a parabola, an ellipse, etc.

Answer 3

not all parabolas are functions
ellipses aren't functions unless you have the left and right raduis is 0 and the up and down radius is 0 then its just a dot and so it is a function

Answer 4

my problem is find the vertex of f(x)=2x^2 it says find and label the vertex and the line of symmetry. do i have to graph it first?

Answer 5

f(x)=2(x-0)^2+0 vertex is (0,0)

Answer 6

i dont know how to find the lines of symmetry

Answer 7

but how do you know that? is it because there is no y intercept?

Answer 8

i put the parabola in vertex form
f(x)=a(x-h)^2+k
where (h,k) is the vertex

Answer 9

okay thanks. i got the symmetry part.

Answer 10

can you tell how you get symmetry part?

Answer 11

can we just since it is even it symmetric about x=0 or the y-axis

Answer 12

yes. its where ever the parabola can be split in half. theres a formula but i cant think of it off the top of my head so i just look at a graph and sometimes there is no line of symmetry

Answer 13

ok thanks nikki :) i put look for the formula later

Answer 14

Symmetry is related to the odd, even function business. An f(-x)=f(x) symmetric about the y axis.
f(-x)=-f(x) symmetric about the origin.