Question

I've got two equations but i cant replace anything in one for the other, how do i figure this out?

A carpenter is building a rectangular room with a fixed perimeter of 356 ft. What dimensions would yield the max. area? What is the max area?

Answer 1

i think the maximum area is a square

Answer 2

There are several ways of doing this, what course is this from?

Answer 3

Algebra 2

Answer 4

Assuming jimmyrep is correct then the sides would be 89 (356/4)

Answer 5

then my area would be 7921?

Answer 6

Yes (assuming jimmyrep is correct)

Answer 7

okay thank you. im just terrible with story problems they catch me off guard

Answer 8

I would wait and see what Nancy Lam has to say

Answer 9

will do

Answer 10

P= (L+W)2
365= (L+W)2
365/2= L+W
182.5 = L+W
182.5/2 =91.25
\[91.25^{2}=8.327?\]

Answer 11

Nancy don't you mean 356?

Answer 12

ok i was wron number, any way use 356 instate 365 my equation is right?

Answer 13

I was with you until the 5th line. what is that about???

Answer 14

Oh, I see you are letting L=W so it would be square. Seems like a burdensome method when you coluld just divide 356 by 4

Answer 15

P= (L+W)2
356= (L+W)2
356/2= L+W
178 = L+W
178/2 =89
\[89^{2}=7.921\]

Answer 16

It appears that Nancy Lam agrees with the 89 answer.

Answer 17

check:
P= (L+W)2
356=(89+89)2
356=178*2
356=356

Answer 18

Thank

Answer 19

You realize niki 150 that this is true, if and only if, the maximum area is a square. I hope jimmyrep is right.

Answer 20

yeah i know. but there is no other way to figure it out so it's gotta be a square. if there was another way there isnt enough information to do so.

Answer 21

Agree, good luck with your studies. Have a good weekend

Answer 22

thanks.

Answer 23

u r we com