Assume that a sample is used to estimate a population mean mu. Use the given confidence level and sample data to find the margin of error. Assume that the sample is a simple random sample and the population has a normal distribution. Round your answer to one more decimal place than the sample standard deviation. 95% confidence; n = 21; x-bar = 0.16; s = 0.16
\[E=(1.96(0.16))/\sqrt{21}\] = 0.068
hey meth.party can u help me after her
I may have done this wrong, Are you looking for the margin of error of the mean or that of the proportion?
margin of error
The error of what exactly?
of population mean mu
If thats what is sought then what I did above should be correct. What course is this?
statistics thank you for all of your help so far
No problem!
how about this one... Find the minimum sample size. You want to be 95% confident that the sample variance is within 20% of the population variance.
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