(x-4)^2/9-(y+2)^2/16=1

give the exact coordinates of any four points on the hyperbola.

and show me how you get this

Question

(x-4)^2/9-(y+2)^2/16=1

give the exact coordinates of any four points on the hyperbola.

and show me how you get this

anonymous · Answer

rework the equation to be an x= or y= equation and go about it that way.  you can put in any point for the variable remaining on the right side and solve it for the missing one.

toxicsugar22 · Answer

i tried can u help me durther please

anonymous · Answer

set up the equation so that the x term is on one side and the y term is on the left, then multiply through by the lowest common demoninator in order to eliminate the fractions.  what do you get?

toxicsugar22 · Answer

can u helo me i dont know how to do this and if u help me with this one i will know for future

anonymous · Answer

move the y term to the right side, which gives you (x-4)^2/9 = (y+2)^2/16 + 1.  multiply both sides of the equation by 9 to eliminate the fraction.  take the square root of both sides in order to eliminate the exponential on the left.  then add 4 to both sides in order to get x alone on the left.  this all gives you$$x = 4 + \sqrt{9(y+2)^2)/16  + 9}$$

anonymous · Answer

then all you have to do is plug in any 4 numbers for x and get the corresponding y points by solving.