Question

3x^2-5x-13=0

Answer 1

Do you have any specific method? remember it can be solved by factoring, or by the general cuadratic formula..

Answer 2

no

Answer 3

give me one minute

Answer 4

okay. thank you for your help.

Answer 5

a = 3;
b = -5;
c = -13

because the discriminant (b^2 - 4 ac = -13) is negative, this equation has not a real solution. Thus, applying the general formula for quadratic equation, we get :
x1=\[1/6(5+i*\sqrt{181})\]
x2=\[1/6(5-i*\sqrt{181})\]

Answer 6

Wait. Ther is a mistake. The discriminant is positive. Gonna fix it

Answer 7

okay. thank you so much.

Answer 8

hi emmunrrad can u help me after her

Answer 9

sure

Answer 10

thanks

Answer 11

Check the attachment

Answer 12

The solution is in the attachment

Answer 13

is that what you want?

Answer 14

Because discriminant is positive, you have two solutions for you equation; they are:
x1 = 3.075604007845618
x2 = -1.40893734117895