Question

(x-4)^2/9-(y+2)^2/16=1

give the exact coordinates of any four points on the hyperbola.

and show me how you get this

Answer 1

hi can u help me

Answer 2

For \(y=-2\) we have \((x-4)^2=9\). Hence\(x-4=\pm 3\). So \(x=4\pm 3\).
Then \((7,-2),(1,-2)\)\) are on the hyperbola.
For \(y=2\) we have \((x-4)^2/9=2\). Then \((x-4)^2=18\). Hence \(x=4\pm 3\sqrt{2}\).
So another two points are \((4+3\sqrt{2},2)\) and \((4-3\sqrt{2},2)\).

Answer 3

thnaks u can also find these points on the graph

Answer 4

can u help me with 2 more

Answer 5

can u help me