give the exact coordinates of any four points on the hyperbola (y+2)^2/6-(x+2)^2/10=1
hi ccan u help me
That's pretty easy. Just choose any 4 points for x, and find the corresponding values of y. I'll do one for you. Let's take x=-2, plug in the equation and solve for x to get: \((y+2)^2/6-0=1\), which implies that \((y+2)^2=6\). Taking the square root of both sides gives \(y+2=\sqrt{6}\), and therefore \(y=\sqrt6-2 \). So, a point on the given hyperbola is \((-2,\sqrt6-2)\).
how about another point
how abut another point for x
Show me what you can do with \(x=8\).
(y+2)^2/6-(8+2)^2/10=1
and then show me by step by step
\[{(y+2)^2 \over 6}-{(8+2)^2 \over 10}=1 \implies {(y+2)^2 \over 6}-{100 \over 10}=1 \implies {(y+2)^2 \over 6}-10=1\] Now take 10 to the other side and then multiply both sides by 6. After that, take the square root and then subtract 2 from both sides. Please TRY :)
*Take -10 to the other side with a positive sign*
so (y+2)^2/6=11
now what do i do
I wrote all steps you need in my last comment; now multiply both sides by 6.
s0 (y+2)^2/36=66
is that rigtht so far
Not quite. It should be, after multiplying by 6: \((y+2)^2=66\).
ok
so now it will be (y+2)^2=8.1240
Yeah, but this is not "exact". You should write it as \((y+2)^2=\sqrt{66}\).
so now what
Sorry I meant \(y+2=\sqrt{66}\). Now take 2 to the other side with a minus sign, and you're done :D
y=sqrt66-2
Yep.
yeah
ok and how about lets try 3 for x
can uwe do an easier number
Go for i!! I am sure you can do it. You will get \(y=\sqrt{21}-2\). I have to go now :(
\(3\) is good.
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