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OpenStudy (anonymous):
can smeone give the general solution of y'= x+y/(2x+2y+3)
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OpenStudy (anonymous):
it is under exact differential equations
OpenStudy (anonymous):
are u sure its not (x+y)/(2x+2y+3) ?
OpenStudy (anonymous):
yes it is
OpenStudy (anonymous):
the take x+y=z and proceed. that is a useful substitution.
OpenStudy (anonymous):
ok will try
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OpenStudy (anonymous):
then what?
OpenStudy (anonymous):
do u have an idea about exact differential equations
OpenStudy (anonymous):
yups but this substitution solves THIS particular sum. if you want a solution with exact differentials i can give u. but u may try this substitution.
OpenStudy (anonymous):
i have but the function will be in z and dy/dx then what should i do
OpenStudy (anonymous):
u will have \[\frac{dz}{dx}=\frac{3z+3}{2z+3}\]
Integrate!
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OpenStudy (anonymous):
dont understand as dy/dx=z/(2z+3) so did u get dz/dx
OpenStudy (anonymous):
use \[x+y=z \implies 1+\frac{dy}{dx}=\frac{dz}{dx}\]
in case u r wondering how i got \[\frac{dz}{dx}\]
OpenStudy (anonymous):
oh u can do that, thanks, u made my day
OpenStudy (anonymous):
I solved it without using the concept of exact differential equations!
OpenStudy (anonymous):
yeah but is it ok to do that? will the answers be the same
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