Question

write a polynomial function in standard form with zero's at -1,-4 and -3

can you please explain the steps?

Answer 1

(x+1)(x+4)(x+3) is I believe what you want

Answer 2

this expands to x^3 +8x^2 +19x + 12

Answer 3

yes thats right but please show me how to expand it

Answer 4

The graph of this function passes through the x-axis at the points where the polynomial = 0 ie whwn x = -1, -3 and -4.

OK first deal with (x+1)(x+4):

first multiply (x+4 by x giving x^2 + 4x
then multiply (x + 4) by +1 giving x + 4

Adding these together gives x^2 + 4x + x +4 = x^2 + 5x + 4

Finally we multiply x^2 + 5x + 4 by the other term (x + 3):

as before first multiply by x then by 3 then add the results together

does this explain it ok? If not get back to me

Answer 5

does it matter what we deal with first? why (x+1)(x+4) and not (X+1)(x+3)

Answer 6

no you'll still get the same result