Question

check for symmetry, y=(x)/(x^2+1) I think thats how you set it up...

Answer 1

check that this is odd.
\[\frac{odd}{even}=odd\] for functions

Answer 2

Im so confused...

Answer 3

ok it is symmetric with respect to the origin.

Answer 4

we can check first with numbers and then with variables.

Answer 5

let x = 1,
\[y=\frac{1}{1^2+1}=\frac{1}{2}\]

Answer 6

now let x = -1
\[y=\frac{-1}{(-1)^2+1}=\frac{-1}{1+1}=-\frac{1}{2}\]

Answer 7

this says go right 1, up one half, left one, down one half.

Answer 8

since we have \[(1,\frac{1}{2})\]
and also \[(-1,-\frac{1}{2})\]

Answer 9

Oh! I see now! Ok, one more... xy^2+10=0, what do you do with the 10?

Answer 10

are you sure? we should check with variables as well.
x = a, get
\[y=\frac{a}{a^2+1}\]
x = -a get
\[y=-\frac{a}{a^2+1}\]

Answer 11

so symmetric wrt the origin.

Answer 12

yeah i get it. the x=1 thing helped

Answer 13

\[xy^2+10=0\]
\[xy^2=-10\]
\[x=-\frac{10}{y^2}\]

Answer 14

ahhhh thank you!

Answer 15

numbers always help

Answer 16

system is weird ignore last remark.

Answer 17

Well thank you very much, helps a lot1