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I don't really know how to type this, but here it goes: log(base5) 4-log(base5) (x+3)= log(base5) 3?
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go ahead :)
\[log_5(4)-log_5(x+3)=log_5(3)\]
just wanted to type it.
ok fine
yeah thats it
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\[log_5(4)-log_5(3)=log_5(x+3)\] \[log_5(\frac{4}{3})=log_5(x+3)\] \[\frac{4}{3}=x+3\]
so i guess \[x=-\frac{5}{3}\]
you switch the 3 and the (x-3?
only log step was using \[log(A)-log(B)=log(\frac{A}{B})\] from right to left.
oh i just added \[log_5(x+3)\] to both sides so it would be positive. easier that way
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sorry it was adding my mistake
added \[log_5(x+3)\] to both sides and subtracted \[log_5(3)\] from both sides so i had the variable by itself on one side.
clear or no?
clear thanks
welcome
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