Question

(z/z^2-8z-9)+8/z+1

Answer 1

i came up with 9z-72/(z-9)(z+1)

Answer 2

factor the 1st denominator
(z+1)(z-9)
this will be the common denominator
\[=\frac{z+8(z-9)}{(z+1)(z-9)}\]
distribute and add like terms on top
9z - 72 = 9(z-8)
\[=\frac{9(z-8)}{(z+1)(z-9)}\]

Answer 3

looks like you got it :)

Answer 4

thank u

Answer 5

\[\sqrt[3]{32^{2}}\]