Question

find the x intercept of a parabola with vertex (3,-2) and y intercept (0,7)

Answer 1

(y+2) = (x-3)^2 +7

y = (x-3)^2 +5

Answer 2

1,-6,14

3 +- sqrt(36 - 4(14))/2 ... aint see it happening

Answer 3

yes I do lol.... its right there

Answer 4

write it in this form (x1,y1)(x2,y2)

Answer 5

(y+2) = (x-3)^2 +C

y = (x-3)^2 +C -2

C-2 = 7; C =9
........................................

y = (x-3)^2 +9

y = x^2 -6x +9 +9; ug, scratch that

y = x^2 -6x +7
..............................

6 +- sqrt(36 -28) sqrt(8)...2sqrt(2)
---------------- =
2

(3 + sqrt(2), 0)

(3 - sqrt(2), 0) maybe lol

Answer 6

\[y=a(x-3)^2-2\]
and
\[7=a(0-3)^2+2\]
\[7=9a+2\]
\[5=9a\]
\[a=\frac{5}{9}\]

Answer 7

yes?

Answer 8

giving \[y=\frac{5}{9}(x-3)^2-2\]

Answer 9

in the (x1,y1) and (x2,y2) form please, i need two intercepts

Answer 10

ok we have the equation for the parabola. finding x- intercepts means setting y = 0 and solve for x.

Answer 11

x^2 -6x + 7 is good

Answer 12

in other words love \[0=\frac{5}{9}(x-3)^2-2\]

Answer 13

i used 0,7 ; 3,-2 ; 6,7 lol

Answer 14

in the (x1,y1) and (x2,y2) form

Answer 15

please

Answer 16

well x-intercept means \[(x_1,0)\]

Answer 17

already did;

(3-sqrt(2),0) and (3+sqrt(2),0)

Answer 18

what equation did you use?

Answer 19

x^2 -6x +7

Answer 20

(y-k)=a(x-h)^2

Answer 21

(y-7)+9 = (x-3)^2

(y+2) = (x-3)^2

Answer 22

boy am i dumb. i wrote \[y=a(x-3)^2+2\] when it should have been \[y=a(x-3)^2-2\]
and \[7=a(-3)^2-2\]
\[7=9a-2\]
\[9=9a\]
\[a=1\]

Answer 23

:) its ok lol

Answer 24

so equation is \[y=(x-3)^2-2\]

Answer 25

idk how to change it to the two points on the graph, please type it that way

Answer 26

or if you prefer
\[y+2=(x-3)^2\]

Answer 27

i posted the points 2 times already...

Answer 28

(3+sqrt(2),0)

(3-sqrt(2),0)

right?

Answer 29

zeros at \[3\pm \sqrt{2}\]

Answer 30

with the parenthesis? and two different points?

Answer 31

with the parenthesis? and two different points?

Answer 32

by inspection

Answer 33

now that 3 and four times lol

Answer 34

\[(2
-\sqrt{3},0)\]
\[(2+\sqrt{3},0)\]

Answer 35

sat lol; that was backwards

Answer 36

are the x-intercepts sorry i slowed you up

Answer 37

oh yes it was!
\[(3-\sqrt{2},0)\]
\[(3+\sqrt{2},0)\]

Answer 38

please in the form of (x1,y1) and (x2,y2) idk what (2-sqrt of 3, 0( means...

Answer 39

means \[x_1=3-\sqrt{2}\]
\[y_1=0\]

Answer 40

it means the the sqrt(2) is an EXACT form of an irrational number that can only be expressed approximately in decimal form; of which we have no way of determining the requirements of since you have given us no parameters to establish them by

Answer 41

and \[x_2=3+\sqrt{2}\]
\[y_2=0\]

Answer 42

y = 0 exactly at:

x = 3-sqrt(2) AND x= 3-sqrt(2) ; otherwise it doesnt...

Answer 43

lol... make one of those a +sqrt(2)

Answer 44

whats x1 and y1?

Answer 45

x1 = 3-sqrt(2)

y1 = 0

Answer 46

its wrong

Answer 47

x1 = 1.414213562373095048801688724209....

no, its right; you simply havent given us a means to approximate the answer.

Answer 48

its like saying; what color is the sky?

blue.

wrong, its a shade of blue that is determined by whatever the criteria is for saying 'blue' in a way that is acceptable...

Answer 49

how old am I ? the right answer depends on how accurate of an answer you want right?