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Mathematics 19 Online
OpenStudy (anonymous):

I have a question on a limit function....

OpenStudy (anonymous):

Let's hear it.

OpenStudy (anonymous):

give me one sec. thanks

OpenStudy (anonymous):

f(x+(delta)x) - f(x)/(delta)x lim as (delta)x approaches 0..... f(x) = x^2 - 4x

OpenStudy (amistre64):

-4?

OpenStudy (watchmath):

good amistre64 :)

OpenStudy (amistre64):

all that verbiage to say; whats f'(0) lol

OpenStudy (anonymous):

I'm getting stuck on the algebra...... I have 2x-4 for some reason

OpenStudy (amistre64):

and when x = 0 what doe you get?

OpenStudy (anonymous):

No, it's (delta)X

OpenStudy (amistre64):

deltax = h; just say h

OpenStudy (anonymous):

(delta)x goes to 0

OpenStudy (anonymous):

ok

OpenStudy (amistre64):

or if you wanna get really wild: delta x = partitional section of the distances from x to som interval that goes to zero; but h is simpler eh lol

OpenStudy (anonymous):

si

OpenStudy (anonymous):

f(x+h) - f(x)/h

OpenStudy (amistre64):

(x+h)^2 -4(x+h)-(x^2 -4x) //h x^2 +h^2 +2xh -4x -4h -x^2+4x//h

OpenStudy (anonymous):

when the function is f(x) = x^2-4

OpenStudy (anonymous):

I'm getting stuck with the 2xh

OpenStudy (amistre64):

cancel the terms that cancel and get: h^2 +2xh -4h//h h + 2x -4 when h = 0 is 2x -4

OpenStudy (amistre64):

the derivative of x^2-4x IS 2x -4

OpenStudy (anonymous):

not taking derivatives yet....

OpenStudy (amistre64):

your learning that the longway to get to the derivative just proves the shortcut methods lol

OpenStudy (anonymous):

ok so 2x-4 is the limit?

OpenStudy (amistre64):

oh yes, you are..

OpenStudy (anonymous):

we are trying to find L

OpenStudy (amistre64):

and yes, the lim would be 2x-4; since the lim as h->0 of f(x) is the definition of a derivative

OpenStudy (anonymous):

OK thank you. I just wanted to make sure.

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