Mathematics
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OpenStudy (anonymous):
I have a question on a limit function....
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OpenStudy (anonymous):
Let's hear it.
OpenStudy (anonymous):
give me one sec. thanks
OpenStudy (anonymous):
f(x+(delta)x) - f(x)/(delta)x lim as (delta)x approaches 0..... f(x) = x^2 - 4x
OpenStudy (amistre64):
-4?
OpenStudy (watchmath):
good amistre64 :)
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OpenStudy (amistre64):
all that verbiage to say; whats f'(0) lol
OpenStudy (anonymous):
I'm getting stuck on the algebra...... I have 2x-4 for some reason
OpenStudy (amistre64):
and when x = 0 what doe you get?
OpenStudy (anonymous):
No, it's (delta)X
OpenStudy (amistre64):
deltax = h; just say h
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OpenStudy (anonymous):
(delta)x goes to 0
OpenStudy (anonymous):
ok
OpenStudy (amistre64):
or if you wanna get really wild: delta x = partitional section of the distances from x to som interval that goes to zero; but h is simpler eh lol
OpenStudy (anonymous):
si
OpenStudy (anonymous):
f(x+h) - f(x)/h
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OpenStudy (amistre64):
(x+h)^2 -4(x+h)-(x^2 -4x) //h
x^2 +h^2 +2xh -4x -4h -x^2+4x//h
OpenStudy (anonymous):
when the function is f(x) = x^2-4
OpenStudy (anonymous):
I'm getting stuck with the 2xh
OpenStudy (amistre64):
cancel the terms that cancel and get:
h^2 +2xh -4h//h
h + 2x -4 when h = 0 is 2x -4
OpenStudy (amistre64):
the derivative of x^2-4x IS 2x -4
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OpenStudy (anonymous):
not taking derivatives yet....
OpenStudy (amistre64):
your learning that the longway to get to the derivative just proves the shortcut methods lol
OpenStudy (anonymous):
ok so 2x-4 is the limit?
OpenStudy (amistre64):
oh yes, you are..
OpenStudy (anonymous):
we are trying to find L
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OpenStudy (amistre64):
and yes, the lim would be 2x-4; since the lim as h->0 of f(x) is the definition of a derivative
OpenStudy (anonymous):
OK thank you. I just wanted to make sure.