Find all asymptotes and intercepts:

y = 2ln(x-3)

How do I find the asymptotes and intercepts? I want to understand the reasoning.

Question

Find all asymptotes and intercepts:

y = 2ln(x-3)

How do I find the asymptotes and intercepts? I want to understand the reasoning.

anonymous · Answer

ln is your clue

anonymous · Answer

I know it should be shifted by 3 to the right and the answer in the back of the book shows that as a vertical asymptote (x = 3), and I know multiplying by 2 will make the function larger. I just don't understand why x = 3 becomes the vertical asymptote and not the x intercept.

anonymous · Answer

Because ln is always greater than 0

amistre64 · Answer

ln(x) never equals 0 or less than 0

amistre64 · Answer

ln(x-3) is undefined at 3 and below

anonymous · Answer

because you can't take ln(0) ?

amistre64 · Answer

you can try, but it like going to newyork to vist the grand canyon; when you get there, it aint gonna happen lol

anonymous · Answer

So how could we write limit notation for the function?

amistre64 · Answer

lim[x->3] ln(x-3) = -inf if anything

amistre64 · Answer

that might have to be adjusted to say 'from the right'

anonymous · Answer

This was actually a question from a graphing exercise. Trying to understand all of this so I can graph these correctly.

anonymous · Answer

Thanks for the help!

amistre64 · Answer

yw :)

anonymous · Answer

Amistre, you did so well on this and that triangle problem earlier, please take a look at this one, one guy is trying to find the answer, and I have tried everything http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4dd992160ada8b0bef2a41c7